The calculation of heat losses is done with the following equation::
Q_v= (2 * pi * lambda * (T_h - T_min)) / (ln * (D/d))
Q_v         Heat loss(W/m)
lambda Thermal conductivity (W/mK)
T_h         Maintain temperature (°C)
T_min     Minimum ambient temperature (worst case) (°C)
ln          natural logarithm
D          pipe diameter including insulation thickness (mm)
            (pipe diameter + 2 x insulation thickness)
d          Outer pipe diameter without insulation(mm)
 

- please read carefully -

Attention: Not all wrong entries will be corrected automatically
For maintain temperature >120°C contact Quintex , please →
Please fill out the entry form as completely as possible.. Fields, which are underlined and shown with  an *  are mandatory for  the calculation (s. formula).
Use checkboxes for the existing entries. The values assigned to the entries will be shown at the related field .This applies to pipes (outer diameter, extra length for valves, supports etc ) and for insulation (thermal conductivity).
Hint: for a meaningful thickness of the insulation: the thickness of the insulation should be approx. the nominal pipe diameter. (eg: DN 50 -> 50mm insulation). Please take care for the thermal resistance of the insulation material. When you have completed your entries, start the design by the appropriate button. A new window will open with the output data (the input data will be repeated), which are shown on a printer friendly page. If all the data correctly, you can print out the design sheet and use it as a documentation of your heating circuit If you have to change your input data just go back to the input window in your browser(should be still open). You can close the output window with a button.